Base | Representation |
---|---|
bin | 100101101100101100011… |
… | …1001011100100000111111 |
3 | 200100022122021022020100021 |
4 | 1023121120321130200333 |
5 | 1134342120313403431 |
6 | 15004115345113011 |
7 | 1043221340312263 |
oct | 113313071344077 |
9 | 20308567266307 |
10 | 5181222012991 |
11 | 1718386830132 |
12 | 6b81a4928767 |
13 | 2b7782c3970b |
14 | 13cab59a20a3 |
15 | 8eb97362b11 |
hex | 4b658e5c83f |
5181222012991 has 2 divisors, whose sum is σ = 5181222012992. Its totient is φ = 5181222012990.
The previous prime is 5181222012937. The next prime is 5181222013001. The reversal of 5181222012991 is 1992102221815.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 5181222012991 - 29 = 5181222012479 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5181222012931) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2590611006495 + 2590611006496.
It is an arithmetic number, because the mean of its divisors is an integer number (2590611006496).
Almost surely, 25181222012991 is an apocalyptic number.
5181222012991 is a deficient number, since it is larger than the sum of its proper divisors (1).
5181222012991 is an equidigital number, since it uses as much as digits as its factorization.
5181222012991 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 51840, while the sum is 43.
The spelling of 5181222012991 in words is "five trillion, one hundred eighty-one billion, two hundred twenty-two million, twelve thousand, nine hundred ninety-one".
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