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5181222013001 is a prime number
BaseRepresentation
bin100101101100101100011…
…1001011100100001001001
3200100022122021022020100122
41023121120321130201021
51134342120313404001
615004115345113025
71043221340312306
oct113313071344111
920308567266318
105181222013001
111718386830141
126b81a4928775
132b7782c39718
1413cab59a20ad
158eb97362b1b
hex4b658e5c849

5181222013001 has 2 divisors, whose sum is σ = 5181222013002. Its totient is φ = 5181222013000.

The previous prime is 5181222012991. The next prime is 5181222013003. The reversal of 5181222013001 is 1003102221815.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 4887972687376 + 293249325625 = 2210876^2 + 541525^2 .

It is a cyclic number.

It is not a de Polignac number, because 5181222013001 - 26 = 5181222012937 is a prime.

It is a super-2 number, since 2×51812220130012 (a number of 26 digits) contains 22 as substring.

Together with 5181222013003, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (5181222013003) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2590611006500 + 2590611006501.

It is an arithmetic number, because the mean of its divisors is an integer number (2590611006501).

Almost surely, 25181222013001 is an apocalyptic number.

It is an amenable number.

5181222013001 is a deficient number, since it is larger than the sum of its proper divisors (1).

5181222013001 is an equidigital number, since it uses as much as digits as its factorization.

5181222013001 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 960, while the sum is 26.

Adding to 5181222013001 its reverse (1003102221815), we get a palindrome (6184324234816).

The spelling of 5181222013001 in words is "five trillion, one hundred eighty-one billion, two hundred twenty-two million, thirteen thousand, one".