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518499670253 is a prime number
BaseRepresentation
bin1111000101110001111…
…11010001100011101101
31211120100010121022222212
413202320333101203231
531443341403422003
61034110115220205
752313622323135
oct7427077214355
91746303538885
10518499670253
1118a992601584
12845a45a7665
1339b81a49316
141b14a15bac5
15d749cdbdd8
hex78b8fd18ed

518499670253 has 2 divisors, whose sum is σ = 518499670254. Its totient is φ = 518499670252.

The previous prime is 518499670211. The next prime is 518499670279. The reversal of 518499670253 is 352076994815.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 516447761449 + 2051908804 = 718643^2 + 45298^2 .

It is a cyclic number.

It is not a de Polignac number, because 518499670253 - 26 = 518499670189 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 518499670192 and 518499670201.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (518499670153) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 259249835126 + 259249835127.

It is an arithmetic number, because the mean of its divisors is an integer number (259249835127).

It is a 1-persistent number, because it is pandigital, but 2⋅518499670253 = 1036999340506 is not.

Almost surely, 2518499670253 is an apocalyptic number.

It is an amenable number.

518499670253 is a deficient number, since it is larger than the sum of its proper divisors (1).

518499670253 is an equidigital number, since it uses as much as digits as its factorization.

518499670253 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 16329600, while the sum is 59.

The spelling of 518499670253 in words is "five hundred eighteen billion, four hundred ninety-nine million, six hundred seventy thousand, two hundred fifty-three".