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51895047437 is a prime number
BaseRepresentation
bin110000010101001011…
…111001010100001101
311221221122200112222222
4300111023321110031
51322240113004222
635501254545125
73515002424252
oct602513712415
9157848615888
1051895047437
1120010446262
12a0836681a5
134b8055b27c
1427242a9429
15153ae25542
hexc152f950d

51895047437 has 2 divisors, whose sum is σ = 51895047438. Its totient is φ = 51895047436.

The previous prime is 51895047419. The next prime is 51895047511. The reversal of 51895047437 is 73474059815.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 48393840196 + 3501207241 = 219986^2 + 59171^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-51895047437 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (51895047937) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25947523718 + 25947523719.

It is an arithmetic number, because the mean of its divisors is an integer number (25947523719).

Almost surely, 251895047437 is an apocalyptic number.

It is an amenable number.

51895047437 is a deficient number, since it is larger than the sum of its proper divisors (1).

51895047437 is an equidigital number, since it uses as much as digits as its factorization.

51895047437 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4233600, while the sum is 53.

The spelling of 51895047437 in words is "fifty-one billion, eight hundred ninety-five million, forty-seven thousand, four hundred thirty-seven".