Base | Representation |
---|---|
bin | 110000011110011111… |
… | …100111011101100101 |
3 | 11222100112112112200121 |
4 | 300132133213131211 |
5 | 1323100102242013 |
6 | 35524554041541 |
7 | 3521610001024 |
oct | 603637473545 |
9 | 158315475617 |
10 | 52051212133 |
11 | 20090609098 |
12 | a107a192b1 |
13 | 4ba6a0810b |
14 | 273ad1a8bb |
15 | 15499c158d |
hex | c1e7e7765 |
52051212133 has 2 divisors, whose sum is σ = 52051212134. Its totient is φ = 52051212132.
The previous prime is 52051212127. The next prime is 52051212149. The reversal of 52051212133 is 33121215025.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 50614650529 + 1436561604 = 224977^2 + 37902^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-52051212133 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 52051212098 and 52051212107.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (52051212233) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26025606066 + 26025606067.
It is an arithmetic number, because the mean of its divisors is an integer number (26025606067).
Almost surely, 252051212133 is an apocalyptic number.
It is an amenable number.
52051212133 is a deficient number, since it is larger than the sum of its proper divisors (1).
52051212133 is an equidigital number, since it uses as much as digits as its factorization.
52051212133 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1800, while the sum is 25.
Adding to 52051212133 its reverse (33121215025), we get a palindrome (85172427158).
The spelling of 52051212133 in words is "fifty-two billion, fifty-one million, two hundred twelve thousand, one hundred thirty-three".
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