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52130201355149 is a prime number
BaseRepresentation
bin10111101101001100000100…
…01000100100001110001101
320211120121011100211021001212
423312212002020210032031
523313100123021331044
6302512141153144205
713660165662243611
oct1366460210441615
9224517140737055
1052130201355149
11156793266a7115
125a1b222b5b065
132311b1a79bc18
14cc31881b9341
1560605d4c6a9e
hex2f698222438d

52130201355149 has 2 divisors, whose sum is σ = 52130201355150. Its totient is φ = 52130201355148.

The previous prime is 52130201355047. The next prime is 52130201355227. The reversal of 52130201355149 is 94155310203125.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 33803968117924 + 18326233237225 = 5814118^2 + 4280915^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-52130201355149 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (52130201355649) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26065100677574 + 26065100677575.

It is an arithmetic number, because the mean of its divisors is an integer number (26065100677575).

Almost surely, 252130201355149 is an apocalyptic number.

It is an amenable number.

52130201355149 is a deficient number, since it is larger than the sum of its proper divisors (1).

52130201355149 is an equidigital number, since it uses as much as digits as its factorization.

52130201355149 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 162000, while the sum is 41.

The spelling of 52130201355149 in words is "fifty-two trillion, one hundred thirty billion, two hundred one million, three hundred fifty-five thousand, one hundred forty-nine".