Base | Representation |
---|---|
bin | 10111101101001100000100… |
… | …01000100100001110001101 |
3 | 20211120121011100211021001212 |
4 | 23312212002020210032031 |
5 | 23313100123021331044 |
6 | 302512141153144205 |
7 | 13660165662243611 |
oct | 1366460210441615 |
9 | 224517140737055 |
10 | 52130201355149 |
11 | 156793266a7115 |
12 | 5a1b222b5b065 |
13 | 2311b1a79bc18 |
14 | cc31881b9341 |
15 | 60605d4c6a9e |
hex | 2f698222438d |
52130201355149 has 2 divisors, whose sum is σ = 52130201355150. Its totient is φ = 52130201355148.
The previous prime is 52130201355047. The next prime is 52130201355227. The reversal of 52130201355149 is 94155310203125.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 33803968117924 + 18326233237225 = 5814118^2 + 4280915^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-52130201355149 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (52130201355649) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26065100677574 + 26065100677575.
It is an arithmetic number, because the mean of its divisors is an integer number (26065100677575).
Almost surely, 252130201355149 is an apocalyptic number.
It is an amenable number.
52130201355149 is a deficient number, since it is larger than the sum of its proper divisors (1).
52130201355149 is an equidigital number, since it uses as much as digits as its factorization.
52130201355149 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 162000, while the sum is 41.
The spelling of 52130201355149 in words is "fifty-two trillion, one hundred thirty billion, two hundred one million, three hundred fifty-five thousand, one hundred forty-nine".
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