Base | Representation |
---|---|
bin | 10111101101001100000100… |
… | …01000100100001100100111 |
3 | 20211120121011100211020221002 |
4 | 23312212002020210030213 |
5 | 23313100123021330142 |
6 | 302512141153143515 |
7 | 13660165662243404 |
oct | 1366460210441447 |
9 | 224517140736832 |
10 | 52130201355047 |
11 | 156793266a7032 |
12 | 5a1b222b5ab9b |
13 | 2311b1a79bb6a |
14 | cc31881b92ab |
15 | 60605d4c6a32 |
hex | 2f6982224327 |
52130201355047 has 2 divisors, whose sum is σ = 52130201355048. Its totient is φ = 52130201355046.
The previous prime is 52130201355041. The next prime is 52130201355149. The reversal of 52130201355047 is 74055310203125.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 52130201355047 - 240 = 51030689727271 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 52130201355047.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (52130201355041) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26065100677523 + 26065100677524.
It is an arithmetic number, because the mean of its divisors is an integer number (26065100677524).
Almost surely, 252130201355047 is an apocalyptic number.
52130201355047 is a deficient number, since it is larger than the sum of its proper divisors (1).
52130201355047 is an equidigital number, since it uses as much as digits as its factorization.
52130201355047 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 126000, while the sum is 38.
The spelling of 52130201355047 in words is "fifty-two trillion, one hundred thirty billion, two hundred one million, three hundred fifty-five thousand, forty-seven".
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