Base | Representation |
---|---|
bin | 100101111011111110111… |
… | …0110110110010000011111 |
3 | 200110110101102010110001011 |
4 | 1023313331312312100133 |
5 | 1140411340402444321 |
6 | 15031145320000051 |
7 | 1045463061443143 |
oct | 113677566662037 |
9 | 20413342113034 |
10 | 5214054343711 |
11 | 17302a4824154 |
12 | 702628300027 |
13 | 2ba8b603b845 |
14 | 14050c249223 |
15 | 90969960ae1 |
hex | 4bdfddb641f |
5214054343711 has 2 divisors, whose sum is σ = 5214054343712. Its totient is φ = 5214054343710.
The previous prime is 5214054343613. The next prime is 5214054343721. The reversal of 5214054343711 is 1173434504125.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 5214054343711 - 217 = 5214054212639 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5214054343721) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2607027171855 + 2607027171856.
It is an arithmetic number, because the mean of its divisors is an integer number (2607027171856).
Almost surely, 25214054343711 is an apocalyptic number.
5214054343711 is a deficient number, since it is larger than the sum of its proper divisors (1).
5214054343711 is an equidigital number, since it uses as much as digits as its factorization.
5214054343711 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 201600, while the sum is 40.
Adding to 5214054343711 its reverse (1173434504125), we get a palindrome (6387488847836).
The spelling of 5214054343711 in words is "five trillion, two hundred fourteen billion, fifty-four million, three hundred forty-three thousand, seven hundred eleven".
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