Base | Representation |
---|---|
bin | 100101111011111110111… |
… | …0110110110001110111101 |
3 | 200110110101102010102220112 |
4 | 1023313331312312032331 |
5 | 1140411340402443423 |
6 | 15031145315555405 |
7 | 1045463061442643 |
oct | 113677566661675 |
9 | 20413342112815 |
10 | 5214054343613 |
11 | 17302a4824075 |
12 | 7026282bbb65 |
13 | 2ba8b603b79b |
14 | 14050c249193 |
15 | 90969960a78 |
hex | 4bdfddb63bd |
5214054343613 has 2 divisors, whose sum is σ = 5214054343614. Its totient is φ = 5214054343612.
The previous prime is 5214054343609. The next prime is 5214054343711. The reversal of 5214054343613 is 3163434504125.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 4232841267769 + 981213075844 = 2057387^2 + 990562^2 .
It is a cyclic number.
It is not a de Polignac number, because 5214054343613 - 22 = 5214054343609 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5214054343513) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2607027171806 + 2607027171807.
It is an arithmetic number, because the mean of its divisors is an integer number (2607027171807).
Almost surely, 25214054343613 is an apocalyptic number.
It is an amenable number.
5214054343613 is a deficient number, since it is larger than the sum of its proper divisors (1).
5214054343613 is an equidigital number, since it uses as much as digits as its factorization.
5214054343613 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 518400, while the sum is 41.
Adding to 5214054343613 its reverse (3163434504125), we get a palindrome (8377488847738).
The spelling of 5214054343613 in words is "five trillion, two hundred fourteen billion, fifty-four million, three hundred forty-three thousand, six hundred thirteen".
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