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52153011034133 is a prime number
BaseRepresentation
bin10111101101110110100011…
…01100100101100000010101
320211122210001000021000022012
423312323101230211200111
523313433331311043013
6302530432411514005
713661634142310462
oct1366732154454025
9224583030230265
1052153011034133
1115687a71114589
125a23729a58905
1323140142b24a9
14cc430d6c4669
15606945c401a8
hex2f6ed1b25815

52153011034133 has 2 divisors, whose sum is σ = 52153011034134. Its totient is φ = 52153011034132.

The previous prime is 52153011034097. The next prime is 52153011034199. The reversal of 52153011034133 is 33143011035125.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 42791510076484 + 9361500957649 = 6541522^2 + 3059657^2 .

It is a cyclic number.

It is not a de Polignac number, because 52153011034133 - 218 = 52153010771989 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 52153011034133.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (52153011034633) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26076505517066 + 26076505517067.

It is an arithmetic number, because the mean of its divisors is an integer number (26076505517067).

Almost surely, 252153011034133 is an apocalyptic number.

It is an amenable number.

52153011034133 is a deficient number, since it is larger than the sum of its proper divisors (1).

52153011034133 is an equidigital number, since it uses as much as digits as its factorization.

52153011034133 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 16200, while the sum is 32.

Adding to 52153011034133 its reverse (33143011035125), we get a palindrome (85296022069258).

The spelling of 52153011034133 in words is "fifty-two trillion, one hundred fifty-three billion, eleven million, thirty-four thousand, one hundred thirty-three".