Base | Representation |
---|---|
bin | 10111101110011001101111… |
… | …10100111000010101111111 |
3 | 20211201120210201101002100101 |
4 | 23313030313310320111333 |
5 | 23314241030003304123 |
6 | 302543235245141531 |
7 | 13663203266005633 |
oct | 1367146764702577 |
9 | 224646721332311 |
10 | 52171904353663 |
11 | 15694a86986146 |
12 | 5a2732125a8a7 |
13 | 2315a3560a7c3 |
14 | cc51c2a0cdc3 |
15 | 60719e755aad |
hex | 2f7337d3857f |
52171904353663 has 2 divisors, whose sum is σ = 52171904353664. Its totient is φ = 52171904353662.
The previous prime is 52171904353649. The next prime is 52171904353691. The reversal of 52171904353663 is 36635340917125.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 52171904353663 - 25 = 52171904353631 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (52171904353643) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26085952176831 + 26085952176832.
It is an arithmetic number, because the mean of its divisors is an integer number (26085952176832).
Almost surely, 252171904353663 is an apocalyptic number.
52171904353663 is a deficient number, since it is larger than the sum of its proper divisors (1).
52171904353663 is an equidigital number, since it uses as much as digits as its factorization.
52171904353663 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 12247200, while the sum is 55.
The spelling of 52171904353663 in words is "fifty-two trillion, one hundred seventy-one billion, nine hundred four million, three hundred fifty-three thousand, six hundred sixty-three".
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