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52208917333 is a prime number
BaseRepresentation
bin110000100111111001…
…001101101101010101
311222202112021210112221
4300213321031231111
51323410440323313
635552350142341
73525533321656
oct604771155525
9158675253487
1052208917333
1120161633371
12a1507b19b1
134c005a41c1
142753c4d52d
151558773c8d
hexc27e4db55

52208917333 has 2 divisors, whose sum is σ = 52208917334. Its totient is φ = 52208917332.

The previous prime is 52208917331. The next prime is 52208917427. The reversal of 52208917333 is 33371980225.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 50165696529 + 2043220804 = 223977^2 + 45202^2 .

It is a cyclic number.

It is not a de Polignac number, because 52208917333 - 21 = 52208917331 is a prime.

Together with 52208917331, it forms a pair of twin primes.

It is a self number, because there is not a number n which added to its sum of digits gives 52208917333.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (52208917331) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26104458666 + 26104458667.

It is an arithmetic number, because the mean of its divisors is an integer number (26104458667).

Almost surely, 252208917333 is an apocalyptic number.

It is an amenable number.

52208917333 is a deficient number, since it is larger than the sum of its proper divisors (1).

52208917333 is an equidigital number, since it uses as much as digits as its factorization.

52208917333 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 272160, while the sum is 43.

The spelling of 52208917333 in words is "fifty-two billion, two hundred eight million, nine hundred seventeen thousand, three hundred thirty-three".