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522143431 is a prime number
BaseRepresentation
bin11111000111110…
…100011011000111
31100101111122010121
4133013310123013
52032132042211
6123451202411
715640101025
oct3707643307
91311448117
10522143431
112488110a7
12126a46407
1384239014
144d4bb715
1530c8e271
hex1f1f46c7

522143431 has 2 divisors, whose sum is σ = 522143432. Its totient is φ = 522143430.

The previous prime is 522143399. The next prime is 522143449. The reversal of 522143431 is 134341225.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 522143431 - 25 = 522143399 is a prime.

It is a super-2 number, since 2×5221434312 = 545267525072903522, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 522143396 and 522143405.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (522143131) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 261071715 + 261071716.

It is an arithmetic number, because the mean of its divisors is an integer number (261071716).

Almost surely, 2522143431 is an apocalyptic number.

522143431 is a deficient number, since it is larger than the sum of its proper divisors (1).

522143431 is an equidigital number, since it uses as much as digits as its factorization.

522143431 is an evil number, because the sum of its binary digits is even.

The product of its digits is 2880, while the sum is 25.

The square root of 522143431 is about 22850.4580041626. The cubic root of 522143431 is about 805.2485278703.

Adding to 522143431 its reverse (134341225), we get a palindrome (656484656).

The spelling of 522143431 in words is "five hundred twenty-two million, one hundred forty-three thousand, four hundred thirty-one".