Base | Representation |
---|---|
bin | 10111110000100000101010… |
… | …11101001001110010010011 |
3 | 20211222111210000212112022211 |
4 | 23320100111131021302103 |
5 | 23321432403042333324 |
6 | 303040415222412551 |
7 | 14001346334101231 |
oct | 1370202535116223 |
9 | 224874700775284 |
10 | 52244342152339 |
11 | 15712779157467 |
12 | 5a39378591157 |
13 | 231c80ab1667c |
14 | cc88d52c3951 |
15 | 608eddda7294 |
hex | 2f8415749c93 |
52244342152339 has 2 divisors, whose sum is σ = 52244342152340. Its totient is φ = 52244342152338.
The previous prime is 52244342152337. The next prime is 52244342152351. The reversal of 52244342152339 is 93325124344225.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 52244342152339 - 21 = 52244342152337 is a prime.
Together with 52244342152337, it forms a pair of twin primes.
It is a junction number, because it is equal to n+sod(n) for n = 52244342152292 and 52244342152301.
It is not a weakly prime, because it can be changed into another prime (52244342152337) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26122171076169 + 26122171076170.
It is an arithmetic number, because the mean of its divisors is an integer number (26122171076170).
Almost surely, 252244342152339 is an apocalyptic number.
52244342152339 is a deficient number, since it is larger than the sum of its proper divisors (1).
52244342152339 is an equidigital number, since it uses as much as digits as its factorization.
52244342152339 is an evil number, because the sum of its binary digits is even.
The product of its digits is 6220800, while the sum is 49.
The spelling of 52244342152339 in words is "fifty-two trillion, two hundred forty-four billion, three hundred forty-two million, one hundred fifty-two thousand, three hundred thirty-nine".
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