Base | Representation |
---|---|
bin | 10111110000100000101010… |
… | …11101001001110010011111 |
3 | 20211222111210000212112100021 |
4 | 23320100111131021302133 |
5 | 23321432403042333401 |
6 | 303040415222413011 |
7 | 14001346334101246 |
oct | 1370202535116237 |
9 | 224874700775307 |
10 | 52244342152351 |
11 | 15712779157478 |
12 | 5a39378591167 |
13 | 231c80ab1668b |
14 | cc88d52c395d |
15 | 608eddda72a1 |
hex | 2f8415749c9f |
52244342152351 has 2 divisors, whose sum is σ = 52244342152352. Its totient is φ = 52244342152350.
The previous prime is 52244342152339. The next prime is 52244342152361. The reversal of 52244342152351 is 15325124344225.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 52244342152351 - 25 = 52244342152319 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 52244342152298 and 52244342152307.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (52244342152361) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26122171076175 + 26122171076176.
It is an arithmetic number, because the mean of its divisors is an integer number (26122171076176).
Almost surely, 252244342152351 is an apocalyptic number.
52244342152351 is a deficient number, since it is larger than the sum of its proper divisors (1).
52244342152351 is an equidigital number, since it uses as much as digits as its factorization.
52244342152351 is an evil number, because the sum of its binary digits is even.
The product of its digits is 1152000, while the sum is 43.
Adding to 52244342152351 its reverse (15325124344225), we get a palindrome (67569466496576).
The spelling of 52244342152351 in words is "fifty-two trillion, two hundred forty-four billion, three hundred forty-two million, one hundred fifty-two thousand, three hundred fifty-one".
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