Base | Representation |
---|---|
bin | 111011100000000000001110… |
… | …0100000010011101101100111 |
3 | 2112122002111022200210111222010 |
4 | 1313000000130200103231213 |
5 | 1022044330142320142100 |
6 | 5053035540200205303 |
7 | 215145043154536662 |
oct | 16700003440235547 |
9 | 2478074280714863 |
10 | 523368013052775 |
11 | 141841145213000 |
12 | 4a848288769833 |
13 | 19605512bc6737 |
14 | 933520b4aa6d9 |
15 | 407900a612750 |
hex | 1dc001c813b67 |
523368013052775 has 96 divisors (see below), whose sum is σ = 951840784290816. Its totient is φ = 253734502560000.
The previous prime is 523368013052743. The next prime is 523368013052791. The reversal of 523368013052775 is 577250310863325.
It is not a de Polignac number, because 523368013052775 - 25 = 523368013052743 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 1330171075 + ... + 1330564475.
It is an arithmetic number, because the mean of its divisors is an integer number (9915008169696).
Almost surely, 2523368013052775 is an apocalyptic number.
523368013052775 is a gapful number since it is divisible by the number (55) formed by its first and last digit.
523368013052775 is a deficient number, since it is larger than the sum of its proper divisors (428472771238041).
523368013052775 is a wasteful number, since it uses less digits than its factorization.
523368013052775 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 406774 (or 406747 counting only the distinct ones).
The product of its (nonzero) digits is 31752000, while the sum is 57.
The spelling of 523368013052775 in words is "five hundred twenty-three trillion, three hundred sixty-eight billion, thirteen million, fifty-two thousand, seven hundred seventy-five".
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