Base | Representation |
---|---|
bin | 10100000001000010001111 |
3 | 100212120200202 |
4 | 110001002033 |
5 | 2320401434 |
6 | 304244115 |
7 | 62412503 |
oct | 24010217 |
9 | 10776622 |
10 | 5247119 |
11 | 2a64269 |
12 | 191063b |
13 | 1119407 |
14 | 9a8303 |
15 | 6d9a7e |
hex | 50108f |
5247119 has 2 divisors, whose sum is σ = 5247120. Its totient is φ = 5247118.
The previous prime is 5247107. The next prime is 5247131. The reversal of 5247119 is 9117425.
It is a balanced prime because it is at equal distance from previous prime (5247107) and next prime (5247131).
It is a cyclic number.
It is not a de Polignac number, because 5247119 - 212 = 5243023 is a prime.
It is a super-3 number, since 3×52471193 (a number of 21 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a Chen prime.
It is equal to p364484 and since 5247119 and 364484 have the same sum of digits, it is a Honaker prime.
It is a junction number, because it is equal to n+sod(n) for n = 5247091 and 5247100.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5247199) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2623559 + 2623560.
It is an arithmetic number, because the mean of its divisors is an integer number (2623560).
Almost surely, 25247119 is an apocalyptic number.
5247119 is a deficient number, since it is larger than the sum of its proper divisors (1).
5247119 is an equidigital number, since it uses as much as digits as its factorization.
5247119 is an evil number, because the sum of its binary digits is even.
The product of its digits is 2520, while the sum is 29.
The square root of 5247119 is about 2290.6590754628. The cubic root of 5247119 is about 173.7695345771.
The spelling of 5247119 in words is "five million, two hundred forty-seven thousand, one hundred nineteen".
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