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52503302043581 is a prime number
BaseRepresentation
bin10111111000000011000001…
…01010101111011110111101
320212220021012101121000120212
423330001200222233132331
523340203230310343311
6303355403423522205
714026144524622004
oct1374014052573675
9225807171530525
1052503302043581
1115802586277604
125a7b5a9759365
13233b06a25164c
14cd725da69c3b
15610ae85c8c8b
hex2fc060aaf7bd

52503302043581 has 2 divisors, whose sum is σ = 52503302043582. Its totient is φ = 52503302043580.

The previous prime is 52503302043529. The next prime is 52503302043583. The reversal of 52503302043581 is 18534020330525.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 38062853640100 + 14440448403481 = 6169510^2 + 3800059^2 .

It is a cyclic number.

It is not a de Polignac number, because 52503302043581 - 210 = 52503302042557 is a prime.

It is a super-2 number, since 2×525033020435812 (a number of 28 digits) contains 22 as substring.

Together with 52503302043583, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (52503302043583) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26251651021790 + 26251651021791.

It is an arithmetic number, because the mean of its divisors is an integer number (26251651021791).

Almost surely, 252503302043581 is an apocalyptic number.

It is an amenable number.

52503302043581 is a deficient number, since it is larger than the sum of its proper divisors (1).

52503302043581 is an equidigital number, since it uses as much as digits as its factorization.

52503302043581 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 432000, while the sum is 41.

The spelling of 52503302043581 in words is "fifty-two trillion, five hundred three billion, three hundred two million, forty-three thousand, five hundred eighty-one".