Base | Representation |
---|---|
bin | 111011101100101100111111… |
… | …1000011000000111000000000 |
3 | 2112212021100112022121200222210 |
4 | 1313121121333003000320000 |
5 | 1022311424242244240000 |
6 | 5100453435401502120 |
7 | 215415123100616604 |
oct | 16731317703007000 |
9 | 2485240468550883 |
10 | 525113423040000 |
11 | 14235439669a053 |
12 | 4aa8a5baaa1940 |
13 | 19700ca246a722 |
14 | 93958a7acb504 |
15 | 40a9612857350 |
hex | 1dd967f0c0e00 |
525113423040000 has 400 divisors, whose sum is σ = 1751671025343360. Its totient is φ = 139744926720000.
The previous prime is 525113423039993. The next prime is 525113423040013. The reversal of 525113423040000 is 40324311525.
It is a tau number, because it is divible by the number of its divisors (400).
It is a Harshad number since it is a multiple of its sum of digits (30).
It is a self number, because there is not a number n which added to its sum of digits gives 525113423040000.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 39 ways as a sum of consecutive naturals, for example, 470802981 + ... + 471917019.
Almost surely, 2525113423040000 is an apocalyptic number.
525113423040000 is a gapful number since it is divisible by the number (50) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 525113423040000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (875835512671680).
525113423040000 is an abundant number, since it is smaller than the sum of its proper divisors (1226557602303360).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
525113423040000 is an equidigital number, since it uses as much as digits as its factorization.
525113423040000 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1114571 (or 1114540 counting only the distinct ones).
The product of its (nonzero) digits is 14400, while the sum is 30.
Adding to 525113423040000 its reverse (40324311525), we get a palindrome (525153747351525).
The spelling of 525113423040000 in words is "five hundred twenty-five trillion, one hundred thirteen billion, four hundred twenty-three million, forty thousand".
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