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52511614502033 is a prime number
BaseRepresentation
bin10111111000010010100000…
…01000010000010010010001
320212221001122200221122220102
423330021100020100102101
523340322241303031113
6303403300324422145
714026560521430521
oct1374112010202221
9225831580848812
1052511614502033
1115806061458685
125a81129547955
13233ba9343510b
14cd780ba2b681
15610e33244758
hex2fc250210491

52511614502033 has 2 divisors, whose sum is σ = 52511614502034. Its totient is φ = 52511614502032.

The previous prime is 52511614502027. The next prime is 52511614502071. The reversal of 52511614502033 is 33020541611525.

It is an a-pointer prime, because the next prime (52511614502071) can be obtained adding 52511614502033 to its sum of digits (38).

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 49547408376064 + 2964206125969 = 7038992^2 + 1721687^2 .

It is a cyclic number.

It is not a de Polignac number, because 52511614502033 - 222 = 52511610307729 is a prime.

It is a super-2 number, since 2×525116145020332 (a number of 28 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (52511614502933) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26255807251016 + 26255807251017.

It is an arithmetic number, because the mean of its divisors is an integer number (26255807251017).

Almost surely, 252511614502033 is an apocalyptic number.

It is an amenable number.

52511614502033 is a deficient number, since it is larger than the sum of its proper divisors (1).

52511614502033 is an equidigital number, since it uses as much as digits as its factorization.

52511614502033 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 108000, while the sum is 38.

The spelling of 52511614502033 in words is "fifty-two trillion, five hundred eleven billion, six hundred fourteen million, five hundred two thousand, thirty-three".