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52515200305541 is a prime number
BaseRepresentation
bin10111111000011001001011…
…10111000000100110000101
320212221101220121021100120202
423330030211313000212011
523340402112234234131
6303405052220540245
714030045422314251
oct1374144567004605
9225841817240522
1052515200305541
111580763155a956
125a8196a3b1685
13233c2152b453c
14cd7a6bd63261
15611092e4ebcb
hex2fc325dc0985

52515200305541 has 2 divisors, whose sum is σ = 52515200305542. Its totient is φ = 52515200305540.

The previous prime is 52515200305499. The next prime is 52515200305553. The reversal of 52515200305541 is 14550300251525.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 39159172237441 + 13356028068100 = 6257729^2 + 3654590^2 .

It is a cyclic number.

It is not a de Polignac number, because 52515200305541 - 222 = 52515196111237 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 52515200305495 and 52515200305504.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (52515200305571) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26257600152770 + 26257600152771.

It is an arithmetic number, because the mean of its divisors is an integer number (26257600152771).

Almost surely, 252515200305541 is an apocalyptic number.

It is an amenable number.

52515200305541 is a deficient number, since it is larger than the sum of its proper divisors (1).

52515200305541 is an equidigital number, since it uses as much as digits as its factorization.

52515200305541 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 150000, while the sum is 38.

The spelling of 52515200305541 in words is "fifty-two trillion, five hundred fifteen billion, two hundred million, three hundred five thousand, five hundred forty-one".