Search a number
-
+
52520388497 is a prime number
BaseRepresentation
bin110000111010011101…
…011000011110010001
312000120020101011122222
4300322131120132101
51330030204412442
640043314110425
73536334636113
oct607235303621
9160506334588
1052520388497
1120301432255
12a218b7b415
134c4cc8a375
14278336b3b3
151575c9b8d2
hexc3a758791

52520388497 has 2 divisors, whose sum is σ = 52520388498. Its totient is φ = 52520388496.

The previous prime is 52520388359. The next prime is 52520388499. The reversal of 52520388497 is 79488302525.

52520388497 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 51821790736 + 698597761 = 227644^2 + 26431^2 .

It is a cyclic number.

It is not a de Polignac number, because 52520388497 - 210 = 52520387473 is a prime.

It is a super-3 number, since 3×525203884973 (a number of 33 digits) contains 333 as substring.

Together with 52520388499, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (52520388499) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26260194248 + 26260194249.

It is an arithmetic number, because the mean of its divisors is an integer number (26260194249).

Almost surely, 252520388497 is an apocalyptic number.

It is an amenable number.

52520388497 is a deficient number, since it is larger than the sum of its proper divisors (1).

52520388497 is an equidigital number, since it uses as much as digits as its factorization.

52520388497 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4838400, while the sum is 53.

The spelling of 52520388497 in words is "fifty-two billion, five hundred twenty million, three hundred eighty-eight thousand, four hundred ninety-seven".