Base | Representation |
---|---|
bin | 10111111000100100100100… |
… | …00110101001101010001101 |
3 | 20212221222200111012200012202 |
4 | 23330102102012221222031 |
5 | 23341002121144000100 |
6 | 303411542441011245 |
7 | 14030353025110166 |
oct | 1374222206515215 |
9 | 225858614180182 |
10 | 52521311312525 |
11 | 1580a18800a950 |
12 | 5a82b94a83b25 |
13 | 233c97a378ac3 |
14 | cd808b7ca76d |
15 | 6112ee6b37d5 |
hex | 2fc4921a9a8d |
52521311312525 has 48 divisors (see below), whose sum is σ = 71964220185600. Its totient is φ = 37704434040000.
The previous prime is 52521311312473. The next prime is 52521311312579.
52521311312525 is nontrivially palindromic in base 10.
It is a de Polignac number, because none of the positive numbers 2k-52521311312525 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 87709586 + ... + 88306364.
It is an arithmetic number, because the mean of its divisors is an integer number (1499254587200).
Almost surely, 252521311312525 is an apocalyptic number.
52521311312525 is a gapful number since it is divisible by the number (55) formed by its first and last digit.
It is an amenable number.
52521311312525 is a deficient number, since it is larger than the sum of its proper divisors (19442908873075).
52521311312525 is a wasteful number, since it uses less digits than its factorization.
52521311312525 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 600930 (or 600925 counting only the distinct ones).
The product of its digits is 90000, while the sum is 38.
It can be divided in two parts, 5252131 and 1312525, that added together give a palindrome (6564656).
The spelling of 52521311312525 in words is "fifty-two trillion, five hundred twenty-one billion, three hundred eleven million, three hundred twelve thousand, five hundred twenty-five".
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