Base | Representation |
---|---|
bin | 11111010011101… |
… | …011001101001001 |
3 | 1100121100112110121 |
4 | 133103223031021 |
5 | 2033431021101 |
6 | 124041543241 |
7 | 16005364123 |
oct | 3723531511 |
9 | 1317315417 |
10 | 525251401 |
11 | 24a544174 |
12 | 127aa4b21 |
13 | 84a8685c |
14 | 4da8a213 |
15 | 311a50a1 |
hex | 1f4eb349 |
525251401 has 2 divisors, whose sum is σ = 525251402. Its totient is φ = 525251400.
The previous prime is 525251399. The next prime is 525251417. The reversal of 525251401 is 104152525.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 288830025 + 236421376 = 16995^2 + 15376^2 .
It is a cyclic number.
It is not a de Polignac number, because 525251401 - 21 = 525251399 is a prime.
It is a super-3 number, since 3×5252514013 (a number of 27 digits) contains 333 as substring.
Together with 525251399, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (525251491) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 262625700 + 262625701.
It is an arithmetic number, because the mean of its divisors is an integer number (262625701).
Almost surely, 2525251401 is an apocalyptic number.
It is an amenable number.
525251401 is a deficient number, since it is larger than the sum of its proper divisors (1).
525251401 is an equidigital number, since it uses as much as digits as its factorization.
525251401 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2000, while the sum is 25.
The square root of 525251401 is about 22918.3638377612. The cubic root of 525251401 is about 806.8430699481.
The spelling of 525251401 in words is "five hundred twenty-five million, two hundred fifty-one thousand, four hundred one".
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