Base | Representation |
---|---|
bin | 1001110010010101… |
… | …00000101111000101 |
3 | 111120011101002011102 |
4 | 10321022200233011 |
5 | 41230012233013 |
6 | 2225203545445 |
7 | 244125316421 |
oct | 47112405705 |
9 | 14504332142 |
10 | 5254024133 |
11 | 225683a106 |
12 | 102768b285 |
13 | 65967cb27 |
14 | 37bb07b81 |
15 | 20b3d2d58 |
hex | 1392a0bc5 |
5254024133 has 2 divisors, whose sum is σ = 5254024134. Its totient is φ = 5254024132.
The previous prime is 5254024091. The next prime is 5254024147. The reversal of 5254024133 is 3314204525.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 4089986209 + 1164037924 = 63953^2 + 34118^2 .
It is a cyclic number.
It is not a de Polignac number, because 5254024133 - 232 = 959056837 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 5254024096 and 5254024105.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5254024933) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2627012066 + 2627012067.
It is an arithmetic number, because the mean of its divisors is an integer number (2627012067).
Almost surely, 25254024133 is an apocalyptic number.
It is an amenable number.
5254024133 is a deficient number, since it is larger than the sum of its proper divisors (1).
5254024133 is an equidigital number, since it uses as much as digits as its factorization.
5254024133 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 14400, while the sum is 29.
The square root of 5254024133 is about 72484.6475676057. The cubic root of 5254024133 is about 1738.4572723198.
Adding to 5254024133 its reverse (3314204525), we get a palindrome (8568228658).
The spelling of 5254024133 in words is "five billion, two hundred fifty-four million, twenty-four thousand, one hundred thirty-three".
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