Base | Representation |
---|---|
bin | 1111010010101001010… |
… | …11011001001000100101 |
3 | 1212020011111100100100001 |
4 | 13221110223121020211 |
5 | 32102013101441042 |
6 | 1041211332221301 |
7 | 52650032006536 |
oct | 7512453311045 |
9 | 1766144310301 |
10 | 525406671397 |
11 | 192907406793 |
12 | 859b176a831 |
13 | 3a7129c034a |
14 | 1b6035ca68d |
15 | da01385bb7 |
hex | 7a54ad9225 |
525406671397 has 2 divisors, whose sum is σ = 525406671398. Its totient is φ = 525406671396.
The previous prime is 525406671389. The next prime is 525406671487. The reversal of 525406671397 is 793176604525.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 516097123201 + 9309548196 = 718399^2 + 96486^2 .
It is a cyclic number.
It is not a de Polignac number, because 525406671397 - 23 = 525406671389 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (525406671197) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 262703335698 + 262703335699.
It is an arithmetic number, because the mean of its divisors is an integer number (262703335699).
Almost surely, 2525406671397 is an apocalyptic number.
It is an amenable number.
525406671397 is a deficient number, since it is larger than the sum of its proper divisors (1).
525406671397 is an equidigital number, since it uses as much as digits as its factorization.
525406671397 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 9525600, while the sum is 55.
The spelling of 525406671397 in words is "five hundred twenty-five billion, four hundred six million, six hundred seventy-one thousand, three hundred ninety-seven".
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