Base | Representation |
---|---|
bin | 100110001110110010100… |
… | …1111010101000000011111 |
3 | 200121022122012111012002102 |
4 | 1030131211033111000133 |
5 | 1142042100020120111 |
6 | 15101505200115315 |
7 | 1051423002665606 |
oct | 114354517250037 |
9 | 20538565435072 |
10 | 5254443520031 |
11 | 1746440425112 |
12 | 70a41a605b3b |
13 | 2c1651912c44 |
14 | 1424603a0a3d |
15 | 91a306be13b |
hex | 4c7653d501f |
5254443520031 has 64 divisors (see below), whose sum is σ = 5968733184000. Its totient is φ = 4595907133440.
The previous prime is 5254443520019. The next prime is 5254443520049. The reversal of 5254443520031 is 1300253444525.
It is a cyclic number.
It is not a de Polignac number, because 5254443520031 - 242 = 856397008927 is a prime.
It is a super-2 number, since 2×52544435200312 (a number of 26 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5254443520831) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 6338290925 + ... + 6338291753.
It is an arithmetic number, because the mean of its divisors is an integer number (93261456000).
Almost surely, 25254443520031 is an apocalyptic number.
5254443520031 is a deficient number, since it is larger than the sum of its proper divisors (714289663969).
5254443520031 is a wasteful number, since it uses less digits than its factorization.
5254443520031 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1992.
The product of its (nonzero) digits is 288000, while the sum is 38.
Adding to 5254443520031 its reverse (1300253444525), we get a palindrome (6554696964556).
The spelling of 5254443520031 in words is "five trillion, two hundred fifty-four billion, four hundred forty-three million, five hundred twenty thousand, thirty-one".
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