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52580131 is a prime number
BaseRepresentation
bin1100100010010…
…0111100100011
310122221100101021
43020210330203
5101430031011
65114550311
71205631562
oct310447443
9118840337
1052580131
112775325a
1215738397
13ab7c906
146da9bd9
154939471
hex3224f23

52580131 has 2 divisors, whose sum is σ = 52580132. Its totient is φ = 52580130.

The previous prime is 52580119. The next prime is 52580141. The reversal of 52580131 is 13108525.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 52580131 - 29 = 52579619 is a prime.

It is a super-2 number, since 2×525801312 = 5529340351954322, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 52580096 and 52580105.

It is not a weakly prime, because it can be changed into another prime (52580141) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26290065 + 26290066.

It is an arithmetic number, because the mean of its divisors is an integer number (26290066).

Almost surely, 252580131 is an apocalyptic number.

52580131 is a deficient number, since it is larger than the sum of its proper divisors (1).

52580131 is an equidigital number, since it uses as much as digits as its factorization.

52580131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1200, while the sum is 25.

The square root of 52580131 is about 7251.2158290869. The cubic root of 52580131 is about 374.6340275465.

Adding to 52580131 its reverse (13108525), we get a palindrome (65688656).

It can be divided in two parts, 525 and 80131, that added together give a square (80656 = 2842).

The spelling of 52580131 in words is "fifty-two million, five hundred eighty thousand, one hundred thirty-one".