Base | Representation |
---|---|
bin | 110000111111111110… |
… | …010111110001100111 |
3 | 12000210200111101102012 |
4 | 300333332113301213 |
5 | 1330222402004341 |
6 | 40100421304435 |
7 | 3541540314344 |
oct | 607776276147 |
9 | 160720441365 |
10 | 52612922471 |
11 | 2034969440a |
12 | a243b6511b |
13 | 4c661b87b5 |
14 | 27917777cb |
15 | 157de790eb |
hex | c3ff97c67 |
52612922471 has 2 divisors, whose sum is σ = 52612922472. Its totient is φ = 52612922470.
The previous prime is 52612922459. The next prime is 52612922473. The reversal of 52612922471 is 17422921625.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 52612922471 - 218 = 52612660327 is a prime.
It is a super-3 number, since 3×526129224713 (a number of 33 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
Together with 52612922473, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (52612922473) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26306461235 + 26306461236.
It is an arithmetic number, because the mean of its divisors is an integer number (26306461236).
Almost surely, 252612922471 is an apocalyptic number.
52612922471 is a deficient number, since it is larger than the sum of its proper divisors (1).
52612922471 is an equidigital number, since it uses as much as digits as its factorization.
52612922471 is an evil number, because the sum of its binary digits is even.
The product of its digits is 120960, while the sum is 41.
The spelling of 52612922471 in words is "fifty-two billion, six hundred twelve million, nine hundred twenty-two thousand, four hundred seventy-one".
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