Base | Representation |
---|---|
bin | 110000111111111111… |
… | …001100101011001111 |
3 | 12000210200220101122101 |
4 | 300333333030223033 |
5 | 1330222430423101 |
6 | 40100430055531 |
7 | 3541542206146 |
oct | 607777145317 |
9 | 160720811571 |
10 | 52613139151 |
11 | 20349822191 |
12 | a24404a5a7 |
13 | 4c66263301 |
14 | 27917d275d |
15 | 157debd401 |
hex | c3ffccacf |
52613139151 has 2 divisors, whose sum is σ = 52613139152. Its totient is φ = 52613139150.
The previous prime is 52613139143. The next prime is 52613139157. The reversal of 52613139151 is 15193131625.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 52613139151 - 23 = 52613139143 is a prime.
It is a super-2 number, since 2×526131391512 (a number of 22 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 52613139151.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (52613139157) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26306569575 + 26306569576.
It is an arithmetic number, because the mean of its divisors is an integer number (26306569576).
Almost surely, 252613139151 is an apocalyptic number.
52613139151 is a deficient number, since it is larger than the sum of its proper divisors (1).
52613139151 is an equidigital number, since it uses as much as digits as its factorization.
52613139151 is an evil number, because the sum of its binary digits is even.
The product of its digits is 24300, while the sum is 37.
The spelling of 52613139151 in words is "fifty-two billion, six hundred thirteen million, one hundred thirty-nine thousand, one hundred fifty-one".
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