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526560664520213 is a prime number
BaseRepresentation
bin111011110111001110111010…
…1010111001000011000010101
32120001101201010001210100022222
41313232131311113020120111
51023004132220104121323
65103522344013232125
7215624516065335641
oct16756356527103025
92501351101710288
10526560664520213
1114286213a793674
124b082b99192645
13197a75c447b58b
14940595a51dc21
1540d20b80b79c8
hex1dee7755c8615

526560664520213 has 2 divisors, whose sum is σ = 526560664520214. Its totient is φ = 526560664520212.

The previous prime is 526560664520197. The next prime is 526560664520251. The reversal of 526560664520213 is 312025466065625.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 312788865762244 + 213771798757969 = 17685838^2 + 14620937^2 .

It is a cyclic number.

It is not a de Polignac number, because 526560664520213 - 24 = 526560664520197 is a prime.

It is a super-2 number, since 2×5265606645202132 (a number of 30 digits) contains 22 as substring.

It is a Sophie Germain prime.

It is a Curzon number.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (526560664522213) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 263280332260106 + 263280332260107.

It is an arithmetic number, because the mean of its divisors is an integer number (263280332260107).

Almost surely, 2526560664520213 is an apocalyptic number.

It is an amenable number.

526560664520213 is a deficient number, since it is larger than the sum of its proper divisors (1).

526560664520213 is an equidigital number, since it uses as much as digits as its factorization.

526560664520213 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 15552000, while the sum is 53.

The spelling of 526560664520213 in words is "five hundred twenty-six trillion, five hundred sixty billion, six hundred sixty-four million, five hundred twenty thousand, two hundred thirteen".