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52741629071981 is a prime number
BaseRepresentation
bin10111111110111110111100…
…00100001101001001101101
320220202001100210221110222122
423333133132010031021231
523403104324020300411
6304101100411122325
714052312510135413
oct1377373604151155
9226661323843878
1052741629071981
1115894665704493
125ab9820a433a5
13235768bb4b045
14d049cc06b2b3
15616de671e9db
hex2ff7de10d26d

52741629071981 has 2 divisors, whose sum is σ = 52741629071982. Its totient is φ = 52741629071980.

The previous prime is 52741629071969. The next prime is 52741629071983. The reversal of 52741629071981 is 18917092614725.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 51633335981956 + 1108293090025 = 7185634^2 + 1052755^2 .

It is a cyclic number.

It is not a de Polignac number, because 52741629071981 - 222 = 52741624877677 is a prime.

It is a super-2 number, since 2×527416290719812 (a number of 28 digits) contains 22 as substring.

Together with 52741629071983, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (52741629071983) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26370814535990 + 26370814535991.

It is an arithmetic number, because the mean of its divisors is an integer number (26370814535991).

Almost surely, 252741629071981 is an apocalyptic number.

It is an amenable number.

52741629071981 is a deficient number, since it is larger than the sum of its proper divisors (1).

52741629071981 is an equidigital number, since it uses as much as digits as its factorization.

52741629071981 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 15240960, while the sum is 62.

The spelling of 52741629071981 in words is "fifty-two trillion, seven hundred forty-one billion, six hundred twenty-nine million, seventy-one thousand, nine hundred eighty-one".