Base | Representation |
---|---|
bin | 110001010111000011… |
… | …011001001101000111 |
3 | 12001210200001210201210 |
4 | 301113003121031013 |
5 | 1332021012140030 |
6 | 40203052222503 |
7 | 3554251354521 |
oct | 612703311507 |
9 | 161720053653 |
10 | 53000115015 |
11 | 20528201951 |
12 | a33176aa33 |
13 | 4cc8494703 |
14 | 27cad66a11 |
15 | 15a2e5cbb0 |
hex | c570d9347 |
53000115015 has 32 divisors (see below), whose sum is σ = 85308926976. Its totient is φ = 28097297280.
The previous prime is 53000115001. The next prime is 53000115019. The reversal of 53000115015 is 51051100035.
53000115015 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 53000115015 - 27 = 53000114887 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 53000114982 and 53000115000.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (53000115019) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 8975554 + ... + 8981456.
It is an arithmetic number, because the mean of its divisors is an integer number (2665903968).
Almost surely, 253000115015 is an apocalyptic number.
53000115015 is a deficient number, since it is larger than the sum of its proper divisors (32308811961).
53000115015 is a wasteful number, since it uses less digits than its factorization.
53000115015 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 9399.
The product of its (nonzero) digits is 375, while the sum is 21.
The spelling of 53000115015 in words is "fifty-three billion, one hundred fifteen thousand, fifteen".
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