Base | Representation |
---|---|
bin | 11111100101110… |
… | …100111110010001 |
3 | 1100221022022001001 |
4 | 133211310332101 |
5 | 2041140310001 |
6 | 124331542001 |
7 | 16064003443 |
oct | 3745647621 |
9 | 1327268031 |
10 | 530010001 |
11 | 2521a43a4 |
12 | 1295ba901 |
13 | 85a617b1 |
14 | 50568493 |
15 | 317e5001 |
hex | 1f974f91 |
530010001 has 2 divisors, whose sum is σ = 530010002. Its totient is φ = 530010000.
The previous prime is 530009947. The next prime is 530010011. The reversal of 530010001 is 100010035.
It is an a-pointer prime, because the next prime (530010011) can be obtained adding 530010001 to its sum of digits (10).
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 481846401 + 48163600 = 21951^2 + 6940^2 .
It is a cyclic number.
It is not a de Polignac number, because 530010001 - 211 = 530007953 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 530010001.
It is not a weakly prime, because it can be changed into another prime (530010011) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 265005000 + 265005001.
It is an arithmetic number, because the mean of its divisors is an integer number (265005001).
Almost surely, 2530010001 is an apocalyptic number.
It is an amenable number.
530010001 is a deficient number, since it is larger than the sum of its proper divisors (1).
530010001 is an equidigital number, since it uses as much as digits as its factorization.
530010001 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 15, while the sum is 10.
The square root of 530010001 is about 23021.9460732580. The cubic root of 530010001 is about 809.2723236646.
Adding to 530010001 its reverse (100010035), we get a palindrome (630020036).
The spelling of 530010001 in words is "five hundred thirty million, ten thousand, one".
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