5300143781 has 2 divisors, whose sum is σ = 5300143782. Its totient is φ = 5300143780.

The previous prime is 5300143769. The next prime is 5300143787. The reversal of 5300143781 is 1873410035.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 4677192100 + 622951681 = 68390^2 + 24959^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-5300143781 is a prime.

It is a super-2 number, since 2×5300143781² = 56183048198545951922, which contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (5300143787) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2650071890 + 2650071891.

It is an arithmetic number, because the mean of its divisors is an integer number (2650071891).

Almost surely, 2^5300143781 is an apocalyptic number.

It is an amenable number.

5300143781 is a deficient number, since it is larger than the sum of its proper divisors (1).

5300143781 is an equidigital number, since it uses as much as digits as its factorization.

5300143781 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 10080, while the sum is 32.

The square root of 5300143781 is about 72802.0863780702. The cubic root of 5300143781 is about 1743.5291674182.

The spelling of 5300143781 in words is "five billion, three hundred million, one hundred forty-three thousand, seven hundred eighty-one".