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53002121 is a prime number
BaseRepresentation
bin1100101000101…
…1111110001001
310200201210020112
43022023332021
5102032031441
65132004105
71212340064
oct312137611
9120653215
1053002121
1127a11307
1215900635
13ac99a03
1470798db
1549be4eb
hex328bf89

53002121 has 2 divisors, whose sum is σ = 53002122. Its totient is φ = 53002120.

The previous prime is 53002109. The next prime is 53002123. The reversal of 53002121 is 12120035.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 52998400 + 3721 = 7280^2 + 61^2 .

It is a cyclic number.

It is not a de Polignac number, because 53002121 - 210 = 53001097 is a prime.

Together with 53002123, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 53002096 and 53002105.

It is not a weakly prime, because it can be changed into another prime (53002123) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26501060 + 26501061.

It is an arithmetic number, because the mean of its divisors is an integer number (26501061).

Almost surely, 253002121 is an apocalyptic number.

It is an amenable number.

53002121 is a deficient number, since it is larger than the sum of its proper divisors (1).

53002121 is an equidigital number, since it uses as much as digits as its factorization.

53002121 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 60, while the sum is 14.

The square root of 53002121 is about 7280.2555587012. The cubic root of 53002121 is about 375.6335860987.

Adding to 53002121 its reverse (12120035), we get a palindrome (65122156).

The spelling of 53002121 in words is "fifty-three million, two thousand, one hundred twenty-one".