Base | Representation |
---|---|
bin | 111100010001000000100101… |
… | …0111100111000010110111011 |
3 | 2120111221101021111100200102002 |
4 | 1320202001022330320112323 |
5 | 1023440203030024434341 |
6 | 5115234032232131215 |
7 | 216441461654603015 |
oct | 17042011274702673 |
9 | 2514841244320362 |
10 | 530103301014971 |
11 | 1439a8602727372 |
12 | 4b5556a2b36b0b |
13 | 199a36b048b968 |
14 | 94c91cb0291b5 |
15 | 414430b61529b |
hex | 1e2204af385bb |
530103301014971 has 2 divisors, whose sum is σ = 530103301014972. Its totient is φ = 530103301014970.
The previous prime is 530103301014953. The next prime is 530103301015049. The reversal of 530103301014971 is 179410103301035.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 530103301014971 - 226 = 530103233906107 is a prime.
It is a super-2 number, since 2×5301033010149712 (a number of 30 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (530103301014871) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 265051650507485 + 265051650507486.
It is an arithmetic number, because the mean of its divisors is an integer number (265051650507486).
Almost surely, 2530103301014971 is an apocalyptic number.
530103301014971 is a deficient number, since it is larger than the sum of its proper divisors (1).
530103301014971 is an equidigital number, since it uses as much as digits as its factorization.
530103301014971 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 34020, while the sum is 38.
The spelling of 530103301014971 in words is "five hundred thirty trillion, one hundred three billion, three hundred one million, fourteen thousand, nine hundred seventy-one".
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