53013453541 has 2 divisors, whose sum is σ = 53013453542. Its totient is φ = 53013453540.

The previous prime is 53013453527. The next prime is 53013453551. The reversal of 53013453541 is 14535431035.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 50017533316 + 2995920225 = 223646^2 + 54735^2 .

It is a cyclic number.

It is not a de Polignac number, because 53013453541 - 2¹¹ = 53013451493 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 53013453497 and 53013453506.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (53013453551) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26506726770 + 26506726771.

It is an arithmetic number, because the mean of its divisors is an integer number (26506726771).

Almost surely, 2^53013453541 is an apocalyptic number.

It is an amenable number.

53013453541 is a deficient number, since it is larger than the sum of its proper divisors (1).

53013453541 is an equidigital number, since it uses as much as digits as its factorization.

53013453541 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 54000, while the sum is 34.

Adding to 53013453541 its reverse (14535431035), we get a palindrome (67548884576).

The spelling of 53013453541 in words is "fifty-three billion, thirteen million, four hundred fifty-three thousand, five hundred forty-one".