Base | Representation |
---|---|
bin | 100110100100101000100… |
… | …1110001000001011110100 |
3 | 200202210201100122011210122 |
4 | 1031021101032020023310 |
5 | 1143324132142120200 |
6 | 15135224014111112 |
7 | 1055003311026056 |
oct | 115112116101364 |
9 | 20683640564718 |
10 | 5301352301300 |
11 | 1764322193840 |
12 | 7175301ab498 |
13 | 2c5bb9110853 |
14 | 1448303418d6 |
15 | 92d789a2385 |
hex | 4d2513882f4 |
5301352301300 has 72 divisors (see below), whose sum is σ = 12550220401152. Its totient is φ = 1927691712000.
The previous prime is 5301352301293. The next prime is 5301352301317. The reversal of 5301352301300 is 31032531035.
It is a self number, because there is not a number n which added to its sum of digits gives 5301352301300.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 35335244 + ... + 35484956.
Almost surely, 25301352301300 is an apocalyptic number.
5301352301300 is a gapful number since it is divisible by the number (50) formed by its first and last digit.
It is an amenable number.
5301352301300 is an abundant number, since it is smaller than the sum of its proper divisors (7248868099852).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
5301352301300 is a wasteful number, since it uses less digits than its factorization.
5301352301300 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 181929 (or 181922 counting only the distinct ones).
The product of its (nonzero) digits is 4050, while the sum is 26.
Adding to 5301352301300 its reverse (31032531035), we get a palindrome (5332384832335).
The spelling of 5301352301300 in words is "five trillion, three hundred one billion, three hundred fifty-two million, three hundred one thousand, three hundred".
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