Base | Representation |
---|---|
bin | 100110100100101000110… |
… | …1100110011110011110101 |
3 | 200202210201220202210201212 |
4 | 1031021101230303303311 |
5 | 1143324141222004214 |
6 | 15135224502331205 |
7 | 1055003436265061 |
oct | 115112154636365 |
9 | 20683656683655 |
10 | 5301360344309 |
11 | 1764326787657 |
12 | 717532a29b05 |
13 | 2c5bba998723 |
14 | 144831436aa1 |
15 | 92d7954053e |
hex | 4d251b33cf5 |
5301360344309 has 2 divisors, whose sum is σ = 5301360344310. Its totient is φ = 5301360344308.
The previous prime is 5301360344257. The next prime is 5301360344317. The reversal of 5301360344309 is 9034430631035.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 4968485580100 + 332874764209 = 2229010^2 + 576953^2 .
It is a cyclic number.
It is not a de Polignac number, because 5301360344309 - 220 = 5301359295733 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5301360344209) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2650680172154 + 2650680172155.
It is an arithmetic number, because the mean of its divisors is an integer number (2650680172155).
Almost surely, 25301360344309 is an apocalyptic number.
It is an amenable number.
5301360344309 is a deficient number, since it is larger than the sum of its proper divisors (1).
5301360344309 is an equidigital number, since it uses as much as digits as its factorization.
5301360344309 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 349920, while the sum is 41.
The spelling of 5301360344309 in words is "five trillion, three hundred one billion, three hundred sixty million, three hundred forty-four thousand, three hundred nine".
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