Base | Representation |
---|---|
bin | 100110100100101000110… |
… | …1100110011110011111101 |
3 | 200202210201220202210202011 |
4 | 1031021101230303303331 |
5 | 1143324141222004232 |
6 | 15135224502331221 |
7 | 1055003436265102 |
oct | 115112154636375 |
9 | 20683656683664 |
10 | 5301360344317 |
11 | 1764326787664 |
12 | 717532a29b11 |
13 | 2c5bba99872b |
14 | 144831436aa9 |
15 | 92d79540547 |
hex | 4d251b33cfd |
5301360344317 has 2 divisors, whose sum is σ = 5301360344318. Its totient is φ = 5301360344316.
The previous prime is 5301360344309. The next prime is 5301360344327. The reversal of 5301360344317 is 7134430631035.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 4877785862041 + 423574482276 = 2208571^2 + 650826^2 .
It is a cyclic number.
It is not a de Polignac number, because 5301360344317 - 23 = 5301360344309 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 5301360344317.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5301360344327) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2650680172158 + 2650680172159.
It is an arithmetic number, because the mean of its divisors is an integer number (2650680172159).
Almost surely, 25301360344317 is an apocalyptic number.
It is an amenable number.
5301360344317 is a deficient number, since it is larger than the sum of its proper divisors (1).
5301360344317 is an equidigital number, since it uses as much as digits as its factorization.
5301360344317 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 272160, while the sum is 40.
The spelling of 5301360344317 in words is "five trillion, three hundred one billion, three hundred sixty million, three hundred forty-four thousand, three hundred seventeen".
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