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5301360344311 = 191118392344439
BaseRepresentation
bin100110100100101000110…
…1100110011110011110111
3200202210201220202210201221
41031021101230303303313
51143324141222004221
615135224502331211
71055003436265063
oct115112154636367
920683656683657
105301360344311
111764326787659
12717532a29b07
132c5bba998725
14144831436aa3
1592d79540541
hex4d251b33cf7

5301360344311 has 8 divisors (see below), whose sum is σ = 5329568563200. Its totient is φ = 5273156838360.

The previous prime is 5301360344309. The next prime is 5301360344317. The reversal of 5301360344311 is 1134430631035.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 5301360344311 - 21 = 5301360344309 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (5301360344317) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1089030 + ... + 3433468.

It is an arithmetic number, because the mean of its divisors is an integer number (666196070400).

Almost surely, 25301360344311 is an apocalyptic number.

5301360344311 is a deficient number, since it is larger than the sum of its proper divisors (28208218889).

5301360344311 is a wasteful number, since it uses less digits than its factorization.

5301360344311 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2356469.

The product of its (nonzero) digits is 38880, while the sum is 34.

Adding to 5301360344311 its reverse (1134430631035), we get a palindrome (6435790975346).

The spelling of 5301360344311 in words is "five trillion, three hundred one billion, three hundred sixty million, three hundred forty-four thousand, three hundred eleven".

Divisors: 1 191 11839 2261249 2344439 447787849 27755813321 5301360344311