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53013847613 is a prime number
BaseRepresentation
bin110001010111110111…
…110001111000111101
312001211121220111022112
4301113313301320331
51332033021110423
640204302423405
73554506161326
oct612767617075
9161747814275
1053013847613
1120534a31401
12a336291b65
134ccb2921cc
1427ccadd44d
1515a4271a78
hexc57df1e3d

53013847613 has 2 divisors, whose sum is σ = 53013847614. Its totient is φ = 53013847612.

The previous prime is 53013847577. The next prime is 53013847639. The reversal of 53013847613 is 31674831035.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 32730960889 + 20282886724 = 180917^2 + 142418^2 .

It is a cyclic number.

It is not a de Polignac number, because 53013847613 - 224 = 52997070397 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (53013840613) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26506923806 + 26506923807.

It is an arithmetic number, because the mean of its divisors is an integer number (26506923807).

Almost surely, 253013847613 is an apocalyptic number.

It is an amenable number.

53013847613 is a deficient number, since it is larger than the sum of its proper divisors (1).

53013847613 is an equidigital number, since it uses as much as digits as its factorization.

53013847613 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 181440, while the sum is 41.

The spelling of 53013847613 in words is "fifty-three billion, thirteen million, eight hundred forty-seven thousand, six hundred thirteen".