53014277441 has 2 divisors, whose sum is σ = 53014277442. Its totient is φ = 53014277440.

The previous prime is 53014277347. The next prime is 53014277443. The reversal of 53014277441 is 14477241035.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 48541343041 + 4472934400 = 220321^2 + 66880^2 .

It is a cyclic number.

It is not a de Polignac number, because 53014277441 - 2¹⁰ = 53014276417 is a prime.

It is a super-2 number, since 2×53014277441² (a number of 22 digits) contains 22 as substring.

Together with 53014277443, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 53014277395 and 53014277404.

It is not a weakly prime, because it can be changed into another prime (53014277443) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26507138720 + 26507138721.

It is an arithmetic number, because the mean of its divisors is an integer number (26507138721).

Almost surely, 2^53014277441 is an apocalyptic number.

It is an amenable number.

53014277441 is a deficient number, since it is larger than the sum of its proper divisors (1).

53014277441 is an equidigital number, since it uses as much as digits as its factorization.

53014277441 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 94080, while the sum is 38.

The spelling of 53014277441 in words is "fifty-three billion, fourteen million, two hundred seventy-seven thousand, four hundred forty-one".