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53014441011 = 3743227258631
BaseRepresentation
bin110001010111111010…
…000010110000110011
312001211200000122022020
4301113322002300303
51332033144103021
640204323242523
73554514212340
oct612772026063
9161750018266
1053014441011
11205352a7214
12a336519443
134ccb43c32c
1427ccc157c7
1515a433c7c6
hexc57e82c33

53014441011 has 32 divisors (see below), whose sum is σ = 83027079168. Its totient is φ = 29458991520.

The previous prime is 53014440989. The next prime is 53014441021. The reversal of 53014441011 is 11014441035.

It is a happy number.

53014441011 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is not a de Polignac number, because 53014441011 - 25 = 53014440979 is a prime.

It is not an unprimeable number, because it can be changed into a prime (53014441021) by changing a digit.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 75666 + ... + 334296.

It is an arithmetic number, because the mean of its divisors is an integer number (2594596224).

Almost surely, 253014441011 is an apocalyptic number.

53014441011 is a deficient number, since it is larger than the sum of its proper divisors (30012638157).

53014441011 is a wasteful number, since it uses less digits than its factorization.

53014441011 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 258911.

The product of its (nonzero) digits is 960, while the sum is 24.

Adding to 53014441011 its sum of digits (24), we get a palindrome (53014441035).

Adding to 53014441011 its reverse (11014441035), we get a palindrome (64028882046).

The spelling of 53014441011 in words is "fifty-three billion, fourteen million, four hundred forty-one thousand, eleven".

Divisors: 1 3 7 21 43 129 227 301 681 903 1589 4767 9761 29283 68327 204981 258631 775893 1810417 5431251 11121133 33363399 58709237 77847931 176127711 233543793 410964659 1232893977 2524497191 7573491573 17671480337 53014441011