Base | Representation |
---|---|
bin | 110001010111111100… |
… | …101001010001011111 |
3 | 12001211201022021212112 |
4 | 301113330221101133 |
5 | 1332033332414124 |
6 | 40204350024235 |
7 | 3554523052634 |
oct | 612774512137 |
9 | 161751267775 |
10 | 53015123039 |
11 | 2053572267a |
12 | a3367a807b |
13 | 4ccb61a8b8 |
14 | 27ccd5218b |
15 | 15a442490e |
hex | c57f2945f |
53015123039 has 4 divisors (see below), whose sum is σ = 54843230760. Its totient is φ = 51187015320.
The previous prime is 53015123017. The next prime is 53015123041. The reversal of 53015123039 is 93032151035.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-53015123039 is a prime.
It is a super-3 number, since 3×530151230393 (a number of 33 digits) contains 333 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 53015122996 and 53015123014.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (53015123089) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 914053817 + ... + 914053874.
It is an arithmetic number, because the mean of its divisors is an integer number (13710807690).
Almost surely, 253015123039 is an apocalyptic number.
53015123039 is a deficient number, since it is larger than the sum of its proper divisors (1828107721).
53015123039 is a wasteful number, since it uses less digits than its factorization.
53015123039 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1828107720.
The product of its (nonzero) digits is 12150, while the sum is 32.
The spelling of 53015123039 in words is "fifty-three billion, fifteen million, one hundred twenty-three thousand, thirty-nine".
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