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530214143 is a prime number
BaseRepresentation
bin11111100110100…
…110110011111111
31100221200200001212
4133212212303333
52041213323033
6124340155035
716065513554
oct3746466377
91327620055
10530214143
11252323808
12129698a7b
1385b036a4
14505bca2b
1531835748
hex1f9a6cff

530214143 has 2 divisors, whose sum is σ = 530214144. Its totient is φ = 530214142.

The previous prime is 530214137. The next prime is 530214149. The reversal of 530214143 is 341412035.

It is a balanced prime because it is at equal distance from previous prime (530214137) and next prime (530214149).

It is a cyclic number.

It is not a de Polignac number, because 530214143 - 212 = 530210047 is a prime.

It is a super-2 number, since 2×5302141432 = 562254074874448898, which contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (530214149) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 265107071 + 265107072.

It is an arithmetic number, because the mean of its divisors is an integer number (265107072).

Almost surely, 2530214143 is an apocalyptic number.

530214143 is a deficient number, since it is larger than the sum of its proper divisors (1).

530214143 is an equidigital number, since it uses as much as digits as its factorization.

530214143 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1440, while the sum is 23.

The square root of 530214143 is about 23026.3792855064. The cubic root of 530214143 is about 809.3762118078.

Adding to 530214143 its reverse (341412035), we get a palindrome (871626178).

The spelling of 530214143 in words is "five hundred thirty million, two hundred fourteen thousand, one hundred forty-three".