Base | Representation |
---|---|
bin | 110001011000011111… |
… | …011110011000111100 |
3 | 12001212100111011111202 |
4 | 301120133132120330 |
5 | 1332043202103000 |
6 | 40205313435032 |
7 | 3554663501231 |
oct | 613037363074 |
9 | 161770434452 |
10 | 53024253500 |
11 | 2053a899509 |
12 | a33986ba78 |
13 | 500049673a |
14 | 27d024b788 |
15 | 15a5129dd5 |
hex | c587de63c |
53024253500 has 48 divisors (see below), whose sum is σ = 116498596032. Its totient is φ = 21082664000.
The previous prime is 53024253467. The next prime is 53024253511. The reversal of 53024253500 is 535242035.
It is a super-3 number, since 3×530242535003 (a number of 33 digits) contains 333 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 234011 + ... + 401010.
It is an arithmetic number, because the mean of its divisors is an integer number (2427054084).
Almost surely, 253024253500 is an apocalyptic number.
53024253500 is a gapful number since it is divisible by the number (50) formed by its first and last digit.
It is an amenable number.
53024253500 is an abundant number, since it is smaller than the sum of its proper divisors (63474342532).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
53024253500 is a wasteful number, since it uses less digits than its factorization.
53024253500 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 635207 (or 635195 counting only the distinct ones).
The product of its (nonzero) digits is 18000, while the sum is 29.
Adding to 53024253500 its reverse (535242035), we get a palindrome (53559495535).
The spelling of 53024253500 in words is "fifty-three billion, twenty-four million, two hundred fifty-three thousand, five hundred".
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