Base | Representation |
---|---|
bin | 111100010010000001011011… |
… | …0010111010000010001011011 |
3 | 2120112102200200102220212001121 |
4 | 1320210002312113100101123 |
5 | 1023444443211230404001 |
6 | 5115422021102430111 |
7 | 216454521332041501 |
oct | 17044026627202133 |
9 | 2515380612825047 |
10 | 530242542044251 |
11 | 143a51665653583 |
12 | 4b578682592337 |
13 | 199b3870a34c4a |
14 | 94d1c3992c671 |
15 | 4147c5a8b66a1 |
hex | 1e240b65d045b |
530242542044251 has 2 divisors, whose sum is σ = 530242542044252. Its totient is φ = 530242542044250.
The previous prime is 530242542044249. The next prime is 530242542044273. The reversal of 530242542044251 is 152440245242035.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 530242542044251 - 21 = 530242542044249 is a prime.
Together with 530242542044249, it forms a pair of twin primes.
It is a junction number, because it is equal to n+sod(n) for n = 530242542044198 and 530242542044207.
It is not a weakly prime, because it can be changed into another prime (530242542084251) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 265121271022125 + 265121271022126.
It is an arithmetic number, because the mean of its divisors is an integer number (265121271022126).
Almost surely, 2530242542044251 is an apocalyptic number.
530242542044251 is a deficient number, since it is larger than the sum of its proper divisors (1).
530242542044251 is an equidigital number, since it uses as much as digits as its factorization.
530242542044251 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1536000, while the sum is 43.
Adding to 530242542044251 its reverse (152440245242035), we get a palindrome (682682787286286).
The spelling of 530242542044251 in words is "five hundred thirty trillion, two hundred forty-two billion, five hundred forty-two million, forty-four thousand, two hundred fifty-one".
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