Base | Representation |
---|---|
bin | 1111011011101001111… |
… | …00100100001101100011 |
3 | 1212200122112202212121212 |
4 | 13231310330210031203 |
5 | 32141414202331202 |
6 | 1043331255540335 |
7 | 53210626142333 |
oct | 7556474441543 |
9 | 1780575685555 |
10 | 530243011427 |
11 | 1949693a1618 |
12 | 8692138a6ab |
13 | 3b0039795cc |
14 | 1b941a490c3 |
15 | dbd5c60652 |
hex | 7b74f24363 |
530243011427 has 2 divisors, whose sum is σ = 530243011428. Its totient is φ = 530243011426.
The previous prime is 530243011391. The next prime is 530243011429. The reversal of 530243011427 is 724110342035.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 530243011427 - 210 = 530243010403 is a prime.
It is a super-5 number, since 5×5302430114275 (a number of 60 digits) contains 55555 as substring.
Together with 530243011429, it forms a pair of twin primes.
It is a Chen prime.
It is a junction number, because it is equal to n+sod(n) for n = 530243011393 and 530243011402.
It is not a weakly prime, because it can be changed into another prime (530243011429) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 265121505713 + 265121505714.
It is an arithmetic number, because the mean of its divisors is an integer number (265121505714).
Almost surely, 2530243011427 is an apocalyptic number.
530243011427 is a deficient number, since it is larger than the sum of its proper divisors (1).
530243011427 is an equidigital number, since it uses as much as digits as its factorization.
530243011427 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 20160, while the sum is 32.
The spelling of 530243011427 in words is "five hundred thirty billion, two hundred forty-three million, eleven thousand, four hundred twenty-seven".
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